Three simple models to explain the observed phenomenon of PRECESSION

by Karl-H. Homann

To download the diagram, please click here

Explanation of the diagram:

A: Sun

B: Earth

C: Sirius

F: Fixed Star

t1: 86164.0905382 s (the mean time period for a complete rotation of the earth on its axis relative to inertial space)

t2: 86400 s (the mean time period for a complete rotation of the earth on its axis relative to the sun)

Obs: Observer

Note:

An observer in space could determine the exact rotation period of t1(using a marked point on earth, e.g. an optical- or a radio source), regardless of any oscillations or a precession of the axis of rotation. By looking horizontally at the plane of our solar system, he would also see the earth "swinging back and forth" at a certain time interval; i.e. at a period of 31,556,925.97474 s. Hence, the observer could easily calculate t2.

THE THREE MODELS:

1. If the axis of the earth precesses, t1 and t2 would increase by 9.12 ms.

2. If the earth moves in a retrograde motion (precessing backwards) around the sun, t1 would increase by 9.12 ms while t2 would have to decrease by 9.12 ms.

3. If the solar system revolves around C, t1 increases by 9.12 ms and t2 remains unchanged.

Since t2 is in reality 86400s, models 1 and 2 are therefore invalid.

COMMENT:

A retrograde precession motion of the axis of rotation also violates the laws of impulse and inertia. Each point along the equator of the earth moves at a velocity of about 465 meters per second. This means, that it is physically impossible for the earth (or any other celestial body for that matter) to move in any form against its direction of rotation without literally ripping apart.

ADDENDUM:

The time interval t1, as measured relative to point C, is identical to the equinoctial or tropical time. Theoretically, if a common centre of gravity exists somewhere between point A and point C (an unequal binary star system), t1 would remain the same. However, either the orbit period or the orbit velocity of A and C around their common centre would have to be less than previously assumed.